regex - Using sed to find lines with specific keywords -

this in bash using centos

i attempting use sed scan text file find lines contain both phrases "define" , "rev_number" (what lies before, in between, , after doesn't matter). however, want ignore lines have "//" in them because these indicate comments (the source file verilog file).

my code follows:

rev=$(sed -n '/define rev_number/p' text.vh <<< $rev) result=$(echo "$rev") 

this covers lines include:

define rev_number 

but want include lines have, say:

define              rev_number 

or number of whitespace between words. ignore lines have

//define rev_number //define      rev_number //    define rev_number 

i stumped how achieve this. new bash/shell scripting , sed. c++ guy using strings.

thanks

you can use sed command:

sed -n '/define  *rev_number/{\~^ *//~!p;}' file define              rev_number