c++ - When I use typedef or using for an int, how much is it still an int? -


i tried following:

using idx = int; array<value, n> arr;  for(idx = 0; < n; ++){   arr[i].dosomething(); }

i expected compiler issue warning or error when try use idx if int. not.

so, when use using or typedef alias type b, variables of type b still of type a, , vice versa? no type safety can achieved renaming type when looks same has different meaning.

(this related following question asked: how make types indexing)

an alias declaration or typedef makes new name aliased type. idx not different type int in case; can used interchangeably no difference in semantics.

from [dcl.typedef] (emphasis mine):

a name declared typedef specifier becomes typedef-name. within scope of declaration, typedef-name syntactically equivalent keyword , names type associated identifier in way described in clause 8. a typedef-name synonym type. typedef-name not introduce new type way class declaration or enum declaration does.


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