c++ - What is the correct way to call the pure virtual member when another member exists with another signature? -

i have pure virtual interface class , derived class this

class iinterface { public:     virtual void func() = 0; };  class myclass : public iinterface { public:     void func(int i) { func(); } };

the compiler complains call func() in func(int i) not take 0 arguments. correct way specify calling pure virtual member?

the 2 solutions came were

void func(int i) { static_cast<iinterface*>(this)->func(); }

and

void func(int i) { iinterface::func(); }

are either of these viable? there better way? both seem clunky.

bring base class declaration derived class scope using-declaration:

class myclass : public iinterface { public:     using iinterface::func;     void func(int i) { func(); } };

alternatively, convert this pointer base work (i.e., first option):

void func(int i) { static_cast<iinterface*>(this)->func(); }

iinterface::func(); won't work, explicit qualification disables virtual dispatch.

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