retrieve data from database using php to android -


i have 3 major tables in database, called place, guideinfo , city. enter city name using android app, , there cityid associated city name. each 3 tables have cityid column.

below php: 

<?php $con=new mysqli("dsfsdf","fsfs","wpraneet","a1575184_touri");  $city=$_post['city'];  if($con->connect_error){      die( "failed connect mysql");      } //$sql1="select *  //from place, guideinfo, city //where place.city_cityid = city.cityid //and city.cityid = guideinfo.city_cityid //and place.city_cityid = guideinfo.city_cityid //and cityname =  '".$city."' //limit 4;";  $sql1="select * place join guideinfo b on a.city_cityid = b.city_cityid join city c on a.city_cityid = c.cityid cityname =  '".$city."' limit 4;"; $result1 = $con->query ($sql1);  if ($result1-> num_rows> 0) {     //output data of each row     while($row1 = $result1->fetch_assoc()) {     echo $row1['placename'];      echo "_";     echo $row1['placetype'];     echo "_";     echo $row1['lat'];     echo "_";     echo $row1['lng'];     echo "_";     echo $row1['shtdes'];     echo "_";     echo $row1['gid'];     echo "_";     echo $row1['gname'];     echo "_";     echo $row1['category'];     echo "_";     echo $row1['telephoneno'];     echo "_";      }         }    $con->close();   ?>

in app want retrieve data four places , four guides in city has been entered , using google maps, mark 4 places.

i have used 2 queries , both mentioned in code. question when there 1 tuple in guideinfo table relevant city entered, map show 4 markers on map.

but if there 2 tuples in guideinfo table relevant city, map show two markers.

i want show four markers , details of 4 guides.

i think there must error in mysql query; should change?

i have trouble following description of problem.

can tell me more specific how expected result looks like? don't see how want details of 4 guides when 2 available.


Comments

Post a Comment

Popular posts from this blog

javascript - Bootstrap Popover: iOS Safari strange behaviour -

i looking through twitter bootstrap documentation, , i'm interested in implementing dismissible popover when button clicked. here example bootstrap's docs: http://getbootstrap.com/javascript/#dismiss-on-next-click when press "dismissible popover" button os x safari browser works fine. when access same link above ios safari, button not work. is, popover not dismissed on click. why button not working ios safari? the example linked using data-trigger="focus" attribute. try changing data-trigger="click" . <a tabindex="0" class="btn btn-lg btn-danger" role="button" data-toggle="popover" data-trigger="click" title="dismissible popover" data-content="and here's amazing content. it's engaging. right?">dismissible popover</a>
Read more

Magento/PHP - Get phones on all members in a customer group -

i working on custom magento extension. working around adminhtml part , i've created custom form there. here form code: <?php class vivasindustries_smsnotification_block_adminhtml_sms_sendmass_edit_form extends mage_adminhtml_block_widget_form { public function _preparelayout() { $extensionpath = mage::getmoduledir('js', 'vivasindustries_smsnotification'); $head = $this->getlayout()->getblock('head'); $head->addjs('jquery.js'); $head->addjs('vivas.js'); return parent::_preparelayout(); } protected function _prepareform() { $form = new varien_data_form(array( 'id' => 'edit_form', 'action' => $this->geturl('*/*/save', array('id' => $this->getrequest()->get...
Read more

session - Logging Out Using PHP -

i have seen other programs regarding can't seem make work. doing wrong? want achieve after user logged out, going previous pages become restricted. i have 3 php files: 1. sample.php - main page username , password filled in 2. successful.php - user's page after logging in 3. logout.php - destorys session hinder user access pages after logging out sample.php </html> <form action="" method="post"> <table> <tr> <td>username:</td> <td>password:</td> </tr> <tr> <td><input type="text" name="username"></td> <td><input type="password" name="password"></td> </tr> <tr> <td><input type="submit" value="submit" name="submit"></td> </tr> </table> </form> </html> <?php $servername = "localhost"; $username = ...
Read more