xml - XSLT with XPath - Wrap children elements with new Parent -


input:

<s:e1 ...>     <s:e2 ...>       <s:child1 ...>          <s:echild1 ...>          ...          </s:echild1 ...>       </s:child1 ...>    </s:e2> </s:e1 ...>

desired output is:

<s:e1 ...>     <s:e2 ...>       <s:xyz>           <s:child1 ...>              <s:echild1 ...>              ...              </s:echild1 ...>           </s:child1 ...>       </s:xyz>    </s:e2> </s:e1 ...>

i.e, want wrap all children elements attributes , children of <s:e2> in <s:xyz>.

xslt came was:

<xsl:stylesheet version="2.0" ...> <xsl:output indent="yes"/>      <xsl:template match="//*:e2">       <s:xyz>         <xsl:apply-templates/>       </s:xyz>     </xsl:template>      <xsl:template match="@*|node()">       <xsl:copy>         <xsl:apply-templates/>       </xsl:copy>     </xsl:template> </xsl:stylesheet>

this generating output <s:xyz> becomes <s:e2>, not direct child element.

try:

<!-- identity transform --> <xsl:template match="@*|node()">     <xsl:copy>         <xsl:apply-templates select="@*|node()"/>     </xsl:copy> </xsl:template>  <xsl:template match="*:e2">     <xsl:copy>         <xyz>             <xsl:apply-templates select="@*|node()"/>         </xyz>     </xsl:copy> </xsl:template>

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