reversing an array AND assigning it to new array in java -

this question has answer here:

• assigning array new variable, changing original changes new one 4 answers

i reverse order of existing array , assign reversed order new array while keeping original array intact (not reverse).

i tried make reverse happen new array (b). however, when print original array after reverse algorithm, prints in new reversed order. array stay intact in original.

here code have 2 arrays: n , b, n original array , b reversed array.

public void setuparray(){     user = input.next();     char [] n  = user.tochararray();      char [] b = n;     boolean ok;      system.out.println(arrays.tostring(n));       for(int = 0; < n.length / 2; i++) // reverses array     {         b[i] = n[i];          char temp = b[i];         b[i] = b[b.length - - 1];         b[b.length - - 1] = temp;      }     system.out.println(arrays.tostring(b));     system.out.println(arrays.tostring(n)); //this prints in reverse reason 

currently if input "hi" scanner, output

[h, i] <-- original array (n) [i, h] <-- reversed array (b) [i, h] <-- orignal array (n) prints in reverse, why??? 

when make assignment

char [] b = n; 

it means there 1 array object referred both n , b variables. create new array in order original array remain unchanged:

char [] b = new char[n.length]; 

if that, code reversing array should change. should take input values n instead of b. don't need temp variable @ all.

for(int = 0; <= n.length / 2; i++) // reverses array {     b[i] = n[b.length - - 1];     b[b.length - - 1] = n[i]; }