java - How do you print out a string exactly as it is? -

i had issue code because file path somehow ended "\n" @ end of path caused issues when trying use file, not able find file.

for debugging purposes, how can print out string including things \b \n \r etc.?

e.g.

system.out.println(file.getabsolutepath).withspecials()

which print console:

c:/folder/filename.extension\n 

you try using code, escapes string. takes care of escapes except \u, should display fine anyway.

public static string escape(string str) {     str = str.replace("\b", "\\b");     str = str.replace("\t", "\\t");     str = str.replace("\n", "\\n");     str = str.replace("\r", "\\r");     str = str.replace("\f", "\\f");     str = str.replace("\'", "\\'");     str = str.replace("\\", "\\\\");     return str; } 

this function can used follows:

system.out.println(escape("123\n\rabc"));