python - How to create DNS TXT record? -


i want create dns txt record type programmatically python code.
did not find data of how doing or specific format of txt record.

here how tried create txt record python:

    # copy id of request     packet+=self.data[:2]     # add flags of response     packet+= "\x81\x80"     # questions , answers counts     packet+='\x00\x01'     packet+='\x00\x01'      #no records follow     packet+='\x00\x00'      # additional records follow     packet+='\x00\x00'     #packet+='\x00\x01'      (urllist,urldatalength) = decodequery(self.data)     urlposition = urldatalength      # original domain name question     packet+=self.data[12:12+urldatalength+4]      # pointer domain name     packet+='\xc0\x0c'                                                   #response type ~~~~~~~~~~~~~~~~     # response type (txt)     packet+='\x00\x10'      #class     packet+='\x00\x01'     #ttl     packet+='\x00\x00\x02\x58'     #data length     packet+='\x00\x04'     #txt length     packet+='\x04'     packet+= 'hi'.encode('hex')

from dnslib (dns.py)

class txt(rd):     """         dns txt record. pass in either single string, or tuple/list of strings.          >>> txt('txtvers=1')         "txtvers=1"         >>> txt(('txtvers=1',))         "txtvers=1"         >>> txt(['txtvers=1',])         "txtvers=1"         >>> txt(['txtvers=1','swver=2.5'])         "txtvers=1","swver=2.5"         >>> = dnsrecord()         >>> a.add_answer(*rr.fromzone('example.com 60 in txt "txtvers=1"'))         >>> a.add_answer(*rr.fromzone('example.com 120 in txt "txtvers=1" "swver=2.3"'))         >>> print(a)         ;; ->>header<<- opcode: query, status: noerror, id: ...         ;; flags: rd; query: 0, answer: 2, authority: 0, additional: 0         ;; answer section:         example.com.            60      in      txt     "txtvers=1"         example.com.            120     in      txt     "txtvers=1" "swver=2.3"     """

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