regex - New line character representation in Java -

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• how split java string @ backslash 6 answers

i have field in database looks this

abcd.\nefgh 

on java side, variable (message), , need split variable on 2 parts: first , second.

something this:

message="abcd.\nefgh" ;//this not happens ??? first = //anything before '\n' second = //anything after '\n' 

i tried following

if(message.indexof('\n')>-1){   first = message.substring(0, message.indexof('\n'));   second = message.substring(message.indexof('\n')) ; } 

however, code never enters body of if statement. checked debugger, , reveals message variable indeed

abcd.\\nefgh 

so, tried use of string.split method,

string rabit = "abcd\\nefgh" ; system.out.println("results \n "+  rabit.split("\n")) ; //1 //and alternative system.out.println("results \n "+  rabit.split("\\n")) ; //2 

however, here problem. in both, 1 , 2 outputs, array 1 element. - full message. pattern not found.

so, can - problem here? fact variable message comes database \n? other suggestions? how can resolve ?

if string contains literal \n need four escape characters in split delimiter regex:

rabit.split("\\\\n")