Python Password Checker -

i need figuring out how make function checks string bunch of conditions.

• passwords must @ least 5 characters long

• passwords must contain @ least 1 upper case letter

• passwords must contain @ least 2 numbers

• passwords may not contain characters "e" or "e"

• passwords must include @ least 1 special symbol: !, @, #, $, %, ^, &

right have

def passwordchecker(password):     '''     '''     caps = sum(1 c in password if c.isupper())     nums = sum(1 c in password if c.isdigit())     symb = any(c in password c in '!@#$%^&')     note = any(c in password c in 'ee')     if len(password) <5:         return false     elif caps < 1:         return false     elif nums < 1:         return false     elif symb == false:         return false     else:         return true 

edit**

just realized have check if there commonly used passwords 'password' or '111111' , dont know how approach this.

just alternative using regular expressions:

import re def passwordchecker(password):     return all(re.search(pattern, password) pattern in                ('.{5}', '[a-z]', '\d.*\d', '^[^ee]*$', '[!@#$%^&]')) 

demo using 5 barely invalid , 5 barely valid tests (one invalid , 1 valid each of 5 rules):

for password in ('1a!',   '12!34', 'a1bc!', 'a12e!', 'a12bc',                  '1a!2.', 'a2!34', 'a12c!', 'a12b!', 'a12b@'):     print(passwordchecker(password)) 

prints false first 5 , true last five.