javascript - Automatically call bind() on all instance methods in es6 during constructor -

how can (or possible to) make javascript base class automatically calls bind on each of instance methods during it's constructor?

i tried, without success:

class baseclass {     constructor() {         // (let in this.__proto__) { // <-- failed         (let in this) {             if (typeof this[i] === 'function') {                 this[i] = this[i].bind(this);             }         }     } }  class myclass extends baseclass {     constructor() {         super();         this.foo = 'bar';     }      mymethod() {         console.log(this.foo);     } } 

when set break point in constructor, this.mymethod exists, , exists in this.__proto__, doesn't in object.getownpropertynames(this) in neither class's constructor nor base class's constructor.

essentially i'm trying bonus step in this blog post (after conclusion) without needing define or call _bind() manually.

es6 class methods non-enumerable, you'd have walk prototype chain yourself.

for (let obj = this; obj; obj = object.getprototypeof(obj)){   (let name of object.getownpropertynames(obj)){     if (typeof this[name] === 'function'){       this[name] = this[name].bind(this);     }   } } 

avoiding complexity why "bonus step" explicitly naming things bind. it's going way slower on every single object create.