R: using grepl, how to only list that is true -


i have list of data , i'm trying divide them , pm groups.

i did

df1 <- split(start, grepl('pm', start$starttime))

which split list am/pm groups. want view evaluate true (i.e. pms).

does have idea?

similar akrun's suggestion:

subset(start, grepl('pm', starttime))

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