c++ - function that calculates sum of proper divisors -


i encountered problem on spoj requires user calculate sum of divisors of number (n) modulus number (m)

http://www.spoj.com/problems/hdevil/

while calculating if use function, spoj gives wa. unable find problem function. advice welcome , appreciated.

int i=0; ll prod=1; while(seive[i]*seive[i]<=n) {     int p=seive[i],j=1;     ll count=1;     while(n%p==0)     {         count+=modpow(p,j,mod);         j++;         n/=p;     }      prod=((prod%mod)*(count%mod))%mod;     i++; } if(n>1) {     prod*=n+1;     prod%=mod; }

here prod final sum , seive[] stores prime numbers , modpow power modulus function.

find factors of n, use divisor summatory function compute sum of divisors of n, taking products modulo m. in problem n < 109, simple factoring function based on trial division sufficient.

ask questions if need additional help.


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