c++ - no operator found which takes a left operand... (using a class template) -

i'm overloading operators of class template , error: error 1 error c2678: binary '>' : no operator found takes left-hand operand of type 'const cset < int >'

cset.h:

bool cset<t>::operator>(const cset<t>& myset) const{      bool flag = false;      (int = 0; < size; i++){         (int j = 0; j < myset.size; j++){             if (arr[i] == myset[j]){                 flag = true;                 break;             }             if (j == myset.size - 1 && flag == false)                 return false;         }     }     return true; }  void cset<t>::operator+=(t& myval){     t* temp = new t[size + 1];     (int = 0; < size; i++){         if (arr[i] == myval){             delete[] temp;             return;         }     }     (int = 0; < size; i++)         temp[i] = arr[i];     delete[] arr;     arr = temp;     arr[size] = myval; } 

mian.cpp:

#include "set.h"   int main(){     cset<int> myset, yourset;     myset += 3; myset += 4; myset += 5;     yourset += 5; yourset += 4; yourset += 3;     bool boom;     boom = myset == yourset; }  

now, error understand compiler cannot convert t int. question is: why not? isn't whole purpose of templates?
there must that's i'm missing because doesn't make sense (at least me).

you want/need change to:

bool cset<t>::operator>(const cset<t>& myset) const {     // ...                                    ^^^^^ note addition here. 

when invoke member function like:

if (x > y) ... 

it's equivalent to: if (x.operator>(y)). const on parameter type means right operand can const. allow left operand const well, add const it's shown above.